corinam9851 corinam9851

02-04-2019
Chemistry

contestada

How many ml of 0.0500 m cacn2 are needed to make 25.0 ml of 0.0150 m solution? The molar mass of cacn2 is 80.11 g/mol.

Respuesta :

11-04-2019

Answer:

= 7.50 mL

Explanation:

m1v1=m2v2

In this case;

m1=0.05

m2=0.015 and

v2=25.00mL

Therefore;

(.0500M)(v1)=(25.00mL)(.0150M)

V1 = ((25.00mL)(0.0150M))/0.0500 M

= 7.50 mL

Answer Link

Otras preguntas

me dan aplicaciones en la medicina de la ley de gauss

When people eat simple carbohydrates, they get _____. A. energy very quickly B. energy slowly, over a long period of time C. information for how to build enzyme

Javier bought 1/2 liter of soda for his party. Javier's brother bought a liter of soda and Javier's mom bought 200 milliliters of soda. How many total millilite

Which language will report a compilation error for the following snippet of code? int i = 3; double n, j = 3.0; n = i + j; Group of answer choices All of the ab

The purpose of this scene is most likely usatestprep

What are the four main ligaments of the knee and where are they located?

Which of the following describes a difference between 19th-century imperialism and forms of imperialism that had existed earlier in history? A. 19th-century imp

Once formed, how many valence electrons does an anion hold?

Please when you answer this show work how you did it.

HELP ME- what is the power of a single voice. DESCRIBE IT