fehaid fehaid
  • 01-02-2021
  • Mathematics
contestada

[tex]x1+2x2-x3=3, 2x1+x2-2x3=1, 3x1+4x2-5x3=5[/tex]

Respuesta :

Аноним Аноним
  • 01-02-2021

Answer: x1 = 0; x2 = 5/3; x3 = 1/3

x1 + 2x2 - x3 = 3 => 2x1 + 4x2 - 2x3 = 6

                                2x1 + x2 - 2x3 = 1

=> 4x2 - x2 = 5

⇔ 3x2 = 5

⇔ x2 = 5/3

with x2 = 5/3, we have: x1 - x3 = 3 - 10/3 = -1/3

                                        3x1 - 5x3 = 5 - 4.5/3 = -5/3

=> x1 = 0

    x3 = 1/3

Step-by-step explanation:

Answer Link

Otras preguntas

Is the square root of -13 rational or irrational or not a real number
Complete the table based on the given domain
What are the genotypes of individuals 2:2 and 2:3?
Consider the noted policy mistakes made by the Federal Reserve during the Depression and explain how each may have contributed to economic decline. “The specula
What’s the focal length of the lens?
Since an instant replay system for tennis was introduced at a major​ tournament, men challenged 1406 referee​ calls, with the result that 416 of the calls were
Identify the graph that represents the equation.5x² = 12y​
What factors led to a revival of the KKK in the 1920s
Find an ordered pair to represent t in the equation t=4u+6v if u=(-1,4) and v=(3,2). a. (14, -4) b. (14, 4) c. (-4,14) d. (4,14)
The sum of two numbers is 13, the difference is 4. What are the numbers?